May Leetcode Challenge - Day 14
Implement a trie with insert, search, and startsWith methods.
Example:
Trie trie = new Trie();
trie.insert("apple");
trie.search("apple"); // returns true
trie.search("app"); // returns false
trie.startsWith("app"); // returns true
trie.insert("app");
trie.search("app"); // returns true
Note:
- You may assume that all inputs are consist of lowercase letters a-z.
- All inputs are guaranteed to be non-empty strings.
Solution
Each node in Trie keeps 3 information: value, list of its child-nodes, and is it a leaf node?
Should use hashtable to keep children.
class TrieNode<T: Hashable> {
var value: T?
weak var parent: TrieNode?
var children = [T: TrieNode]()
var isTerminate: Bool = false
init(_ value: T? = nil, _ parent: TrieNode? = nil) {
self.value = value
self.parent = parent
}
func addChild(_ value: T) -> TrieNode? {
guard children[value] == nil else {
return nil
}
children[value] = TrieNode(value, self)
return children[value]
}
}
class Trie {
typealias Node = TrieNode<Character>
private var root: Node
/** Initialize your data structure here. */
init() {
root = Node()
}
/** Inserts a word into the trie. */
func insert(_ word: String) {
guard !word.isEmpty else { return }
var currentNode: Node? = root
var count = 0
for char in word.lowercased() {
if let child = currentNode?.children[char] {
currentNode = child
}else {
currentNode = currentNode?.addChild(char)
}
count += 1
if count == word.count {
currentNode?.isTerminate = true
}
}
}
/** Returns if the word is in the trie. */
func search(_ word: String) -> Bool {
guard !word.isEmpty else { return false }
var currentNode: Node? = root
for char in word.lowercased() {
currentNode = currentNode?.children[char]
if currentNode == nil { break }
}
return currentNode != nil && currentNode!.isTerminate
}
/** Returns if there is any word in the trie that starts with the given prefix. */
func startsWith(_ prefix: String) -> Bool {
guard !prefix.isEmpty else { return false }
var currentNode: Node? = root
for char in prefix.lowercased() {
currentNode = currentNode?.children[char]
if currentNode == nil { break }
}
return currentNode != nil
}
}